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0=-4.9x^2+49x-98.5
We move all terms to the left:
0-(-4.9x^2+49x-98.5)=0
We add all the numbers together, and all the variables
-(-4.9x^2+49x-98.5)=0
We get rid of parentheses
4.9x^2-49x+98.5=0
a = 4.9; b = -49; c = +98.5;
Δ = b2-4ac
Δ = -492-4·4.9·98.5
Δ = 470.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-\sqrt{470.4}}{2*4.9}=\frac{49-\sqrt{470.4}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+\sqrt{470.4}}{2*4.9}=\frac{49+\sqrt{470.4}}{9.8} $
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